document.write( "Question 459327: Please note that graphing is not allowed in solving this.\r
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document.write( "If x^2+y^2=9 and x-3y=3, then what are the values of x and y? \n" );
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Algebra.Com's Answer #317307 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! If x^2+y^2=9 and x-3y=3, then what are the values of x and y? \n" ); document.write( ".. \n" ); document.write( "x^2+y^2=9 \n" ); document.write( "x-3y=3 \n" ); document.write( ".. \n" ); document.write( "3y=x-3 \n" ); document.write( "y=(x-3)/3 \n" ); document.write( ".. \n" ); document.write( "x^2+y^2=9 \n" ); document.write( "x^2+[(x-3)/3]^2=9 \n" ); document.write( "x^2+(x^2-6x+9)/9=9 \n" ); document.write( "LCD:9 \n" ); document.write( "9x^2+x^2-6x+9=81 \n" ); document.write( "10x^2-6x-81=0 \n" ); document.write( "solve by quadratic formula: \n" ); document.write( "a=10, b=-6, c=-81 \n" ); document.write( "x=]-(-6)ħsqrt((-6)^2-4*10*(-81)]/2*10 \n" ); document.write( "x=[6ħsqrt(3276)]/20 \n" ); document.write( "x=(6ħ57.24)/20 \n" ); document.write( "x=3.16 \n" ); document.write( "y=(3.16-3)/3=.0533 \n" ); document.write( "or \n" ); document.write( "x=-2.56 \n" ); document.write( "y=(-2.56-3)/3=-1.85 \n" ); document.write( " |