document.write( "Question 459327: Please note that graphing is not allowed in solving this.\r
\n" ); document.write( "\n" ); document.write( "If x^2+y^2=9 and x-3y=3, then what are the values of x and y?
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Algebra.Com's Answer #317307 by lwsshak3(11628)\"\" \"About 
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If x^2+y^2=9 and x-3y=3, then what are the values of x and y?
\n" ); document.write( "..
\n" ); document.write( "x^2+y^2=9
\n" ); document.write( "x-3y=3
\n" ); document.write( "..
\n" ); document.write( "3y=x-3
\n" ); document.write( "y=(x-3)/3
\n" ); document.write( "..
\n" ); document.write( "x^2+y^2=9
\n" ); document.write( "x^2+[(x-3)/3]^2=9
\n" ); document.write( "x^2+(x^2-6x+9)/9=9
\n" ); document.write( "LCD:9
\n" ); document.write( "9x^2+x^2-6x+9=81
\n" ); document.write( "10x^2-6x-81=0
\n" ); document.write( "solve by quadratic formula:
\n" ); document.write( "a=10, b=-6, c=-81
\n" ); document.write( "x=]-(-6)ħsqrt((-6)^2-4*10*(-81)]/2*10
\n" ); document.write( "x=[6ħsqrt(3276)]/20
\n" ); document.write( "x=(6ħ57.24)/20
\n" ); document.write( "x=3.16
\n" ); document.write( "y=(3.16-3)/3=.0533
\n" ); document.write( "or
\n" ); document.write( "x=-2.56
\n" ); document.write( "y=(-2.56-3)/3=-1.85
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