document.write( "Question 462980: find the vertex of the parabola: x^2-4x-4y+16=0 \n" ); document.write( "
Algebra.Com's Answer #317282 by lwsshak3(11628)\"\" \"About 
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find the vertex of the parabola: x^2-4x-4y+16=0
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\n" ); document.write( "Standard form of parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex) A is a multiplier which affects the steepness of the curve.
\n" ); document.write( " x^2-4x-4y+16=0
\n" ); document.write( "4y=x^2-4x+16
\n" ); document.write( "divide by 4
\n" ); document.write( "y=(1/4)(x^2-4x+16)
\n" ); document.write( "completing the square
\n" ); document.write( "y=(1/4)(x^2-4x+4)+4-1
\n" ); document.write( "y=(1/4)(x-2)^2+3
\n" ); document.write( "coordinates of the vertex: (2,3)
\n" ); document.write( "see the graph below as a visual check on the answer
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%281%2F4%29%28x%5E2-4x%2B16%29%29+\"
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