document.write( "Question 462980: find the vertex of the parabola: x^2-4x-4y+16=0 \n" ); document.write( "
Algebra.Com's Answer #317282 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! find the vertex of the parabola: x^2-4x-4y+16=0 \n" ); document.write( ".. \n" ); document.write( "Standard form of parabola: y=A(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex) A is a multiplier which affects the steepness of the curve. \n" ); document.write( " x^2-4x-4y+16=0 \n" ); document.write( "4y=x^2-4x+16 \n" ); document.write( "divide by 4 \n" ); document.write( "y=(1/4)(x^2-4x+16) \n" ); document.write( "completing the square \n" ); document.write( "y=(1/4)(x^2-4x+4)+4-1 \n" ); document.write( "y=(1/4)(x-2)^2+3 \n" ); document.write( "coordinates of the vertex: (2,3) \n" ); document.write( "see the graph below as a visual check on the answer \n" ); document.write( "..\r \n" ); document.write( "\n" ); document.write( " |