document.write( "Question 462929: A store mixes Brazilian coffee worth $10 per kilogram and Turkish coffee worth $14 per kilogram. The mixture is to sell for $13 per kilogram. Find how much of each should be used to make a 528-kilogram mixture.
\n" ); document.write( "How many kilograms of the Brazilian coffee should be in the mixture?
\n" ); document.write( "How many kilograms of the Turkish coffee should be in the mixture?
\n" ); document.write( "

Algebra.Com's Answer #317272 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A store mixes Brazilian coffee worth $10 per kilogram and Turkish coffee worth $14 per kilogram. The mixture is to sell for $13 per kilogram.
\n" ); document.write( "Find how much of each should be used to make a 528-kilogram mixture.
\n" ); document.write( "-------------------
\n" ); document.write( "Quantity Equation: B + T = 528 kgr
\n" ); document.write( "Value Equation::: 10B+14T = 13*528
\n" ); document.write( "------------------------
\n" ); document.write( "Multiply thru the 1st equation by 10:
\n" ); document.write( "10B + 10T = 10*528
\n" ); document.write( "10B + 14T = 13*528
\n" ); document.write( "------
\n" ); document.write( "Subtract and solve for \"T\":
\n" ); document.write( "4T = 3*528
\n" ); document.write( "--------------
\n" ); document.write( "T = 3*132
\n" ); document.write( "T = 396 kgr (amt. of Turkish coffee needed)
\n" ); document.write( "-----
\n" ); document.write( "Solve for \"B\":
\n" ); document.write( "B + T = 528
\n" ); document.write( "B + 396 = 528
\n" ); document.write( "B = 132 kgr (amt of Brazilian coffee needed)
\n" ); document.write( "=================================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=============\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "How many kilograms of the Brazilian coffee should be in the mixture?
\n" ); document.write( "How many kilograms of the Turkish coffee should be in the mixture?
\n" ); document.write( "
\n" ); document.write( "
\n" );