document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462887>Question 462887</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of angle SQR is 2/5 the measure of angle PQR is 2/3 the measure of a right angle, what is the measure of a right angle, what is the measure of angle SQR. \r<BR>\n" );
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document.write( "HERE'S ANOTHER QUESTION\r<BR>\n" );
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document.write( "In Isosceles triangle ABC, the measure of angle A is 80 degrees. If another angle of the triangle measure x degrees, x &#8800; 80, what is one possible value of x?\r<BR>\n" );
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document.write( "Here's Another \r<BR>\n" );
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document.write( "If r is directly proportional to s and if s= 2/3 when r=4/5, what is the value of r when s=4/9 ? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317270 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317270\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (2/3)/(4/5)=(4/9)/(r)<BR>\n" );
document.write( "2/3r=16/45<BR>\n" );
document.write( "r=(16/45)/(2/3)<BR>\n" );
document.write( "r=16/45*3/2<BR>\n" );
document.write( "r=48/90<BR>\n" );
document.write( "r=8/15 </SPAN>\n" );
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