document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462759>Question 462759</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how much of an alloy that is 10% copper should be mixed with 400 ounces of an alloy that is 80% copper in order to get an alloy that is 30% copper </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317238 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317238\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .1r+.8(400)=.3(r+400)<BR>\n" );
document.write( ".1r+320=.3r+120<BR>\n" );
document.write( ".2r=200<BR>\n" );
document.write( "r=200/.2=1000<BR>\n" );
document.write( "You need 1000 ozs. of 10% copper for your mix.<BR>\n" );
document.write( "1400x.3=420<BR>\n" );
document.write( "100+320=420.. </SPAN>\n" );
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