document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=458434>Question 458434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Assume that a jeweler needs 55 grams of an alloy that is 50% gold. He has available one alloy that is 25% gold, and another that is 70% gold; he will mix some of each.\r<BR>\n" );
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document.write( "If x= number of grams of the first alloy (so the number of grams of the second is 55-x), find x.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317236 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317236\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 55x.5=27.5<BR>\n" );
document.write( "w+z=55<BR>\n" );
document.write( ".25w+.7z=27.5<BR>\n" );
document.write( "25w+70z=2750<BR>\n" );
document.write( "25w+25z=1375<BR>\n" );
document.write( "45z=1375<BR>\n" );
document.write( "z=30.55555<BR>\n" );
document.write( "w=24.44444<BR>\n" );
document.write( "You need 24.4444 gms. of 25% gold and 30.555555 gms. of 70% gold for your mix..<BR>\n" );
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