document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47962>Question 47962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 3in. more than twice its width. If the perimeter of the rectangle is 36in., find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31723 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31723\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> PERIMETER =2*LENGTH+2*WIDTH OR LENGTH IS 2W+3 AND W=WIDTH THUS\r<BR>\n" );
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document.write( "2(2W+3)+2W=36 OR 4W+6+2W=36 OR 6W=30 OR W=30/6 OR W=5 \r<BR>\n" );
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document.write( "PROOF 2*5+2(2*5+3)=36 OR 10+2(13)=36 OR 10+26=36 OR 36=36  </SPAN>\n" );
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