document.write( "Question 458341: How much pure acid should be mixed with 4 gallons of a 30% acid solution in order to get an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #317229 by jorel1380(3719)\"\" \"About 
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z+.30(4)=.80(z+4)
\n" ); document.write( "z+1.2=.8z+3.2
\n" ); document.write( ".2z=2
\n" ); document.write( "z=2/.2=10
\n" ); document.write( "You need 10 liters of pure acid for your mix
\n" ); document.write( "10(1)+4(.30)=14(.8)
\n" ); document.write( "10+1.2=11.2
\n" ); document.write( "11.2=11.2..
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