document.write( "Question 458341: How much pure acid should be mixed with 4 gallons of a 30% acid solution in order to get an 80% acid solution? \n" ); document.write( "
Algebra.Com's Answer #317229 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! z+.30(4)=.80(z+4) \n" ); document.write( "z+1.2=.8z+3.2 \n" ); document.write( ".2z=2 \n" ); document.write( "z=2/.2=10 \n" ); document.write( "You need 10 liters of pure acid for your mix \n" ); document.write( "10(1)+4(.30)=14(.8) \n" ); document.write( "10+1.2=11.2 \n" ); document.write( "11.2=11.2.. \n" ); document.write( " |