document.write( "Question 462627: How many liters of water must be added to 90 liters of an 80% solution of antifreeze and water to obtain a 60% antifreeze solution? \n" ); document.write( "

Algebra.Com's Answer #317217 by jorel1380(3719) $\"\"$ $\"About$

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90x.80=72
\n" ); document.write( ".60x=72
\n" ); document.write( "x=72/.60=120
\n" ); document.write( "Since you already have 90 liters of solution, you need to add 30 liters of pure water to get the desired mix.
\n" ); document.write( "90x.8=72
\n" ); document.write( "120x.60=72.. \n" ); document.write( "

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