document.write( "Question 462837: Brad is 6 years older than Pedro. Five years ago Pedro's age was three-fourths of Brad's age at that time. Find the present ages of Brad and Pedro. \n" ); document.write( "
Algebra.Com's Answer #317203 by algebrahouse.com(1659)\"\" \"About 
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x = Pedro's age now
\n" ); document.write( "x + 6 = Brad's age now\r
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\n" ); document.write( "\n" ); document.write( "x - 5 = Pedro's age five years ago
\n" ); document.write( "x + 1 = Brad's age five years ago\r
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\n" ); document.write( "\n" ); document.write( "x - 5 = (3/4)(x + 1) {five years ago Pedro's age was 3/4 Brad's age}
\n" ); document.write( "4[x - 5 = (3/4)(x + 1)] {multiplied entire equation by 4 to clear out fractions}
\n" ); document.write( "4(x) + 4(-5) = 4(3/4)(x + 1) {multiplied each term by 4}
\n" ); document.write( "4x - 20 = 3(x + 1) {multiplied through}
\n" ); document.write( "4x - 20 = 3x + 3 {used distributive property}
\n" ); document.write( "x - 20 = 3 {subtracted 3x from both sides}
\n" ); document.write( "x = 23 {added 20 to both sides}
\n" ); document.write( "x + 6 = 29 {substituted 23, in for x, into x + 6}\r
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\n" ); document.write( "\n" ); document.write( "Pedro is 23 and Brad is 29
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