document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462726>Question 462726</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the surface area of a prism whose bases are right triangles? The side measures are 2 meters, 3 meters, and 4 meters, and the height is 5. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317191 by </B><A HREF=/tutors/aboutme.mpl?userid=math-vortex><B>math-vortex(648)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math-vortex><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math-vortex><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> What is the surface area of a prism whose bases are right triangles? The side measures are 2 meters, 3 meters, and 4 meters, and the height is 5.<BR>\n" );
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document.write( "If I read your problem correctly, this is a right triangular prism with a height of 5. The side measures the triangular base are 2 meters, 3 meters, and 4 meters.<BR>\n" );
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document.write( "We cannot have a right triangle with those measurements because the Pythagorean Theorem does not hold...2-squared plus 3-squares does not equal 4-squared. I think you might be that the measures of the side measures of the triangle are 3m, 4m, and 5m, and the height is 2 m.<BR>\n" );
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document.write( "That's the problem I'll solve. If this is not the case, you can resubmit or send me a message.<BR>\n" );
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document.write( "To find the surface area, we need to calculate the area of the two bases, as well as the area of the three sides.<BR>\n" );
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document.write( "The formula for the area A of a right triangle is <BR>\n" );
document.write( "A = (1/2)*b*h<BR>\n" );
document.write( "where b is the base and h is the height. Using the values given in the modified problem, we have<BR>\n" );
document.write( "A = (1/2)(3)(4) = 6<BR>\n" );
document.write( "So the area of each triangle base is 6 square meters.<BR>\n" );
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document.write( "Now we need the area of each side of the prism. The shapes of the sides are rectangles measuring <BR>\n" );
document.write( "3 by 2 square meters<BR>\n" );
document.write( "4 by 2 square meters<BR>\n" );
document.write( "5 by 2 square meters<BR>\n" );
document.write( "The formula for the area A of a rectangle is s*h here s is the side length of the triangle, and h is the height of the prism. (This is just a variation on area=length times width.)<BR>\n" );
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document.write( "The rectangles measure<BR>\n" );
document.write( "(3)(2) = 6 square meters,<BR>\n" );
document.write( "(4)(2) = 8 square meters, and <BR>\n" );
document.write( "(5)(2) = 10 square meters.<BR>\n" );
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document.write( "Now we just add up the area of each face of the prim to get the surface area SA.<BR>\n" );
document.write( "SA = 6 + 6 + 6 + 8 + 10 = 36 square meters.<BR>\n" );
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document.write( "hope this helps!<BR>\n" );
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document.write( "Ms.Figgy<BR>\n" );
document.write( "math.in.the.vortex\r<BR>\n" );
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