document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462738>Question 462738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Determine (-2+i3)^5 in the polar form and in cartesian form </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317163 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Determine (-2+i3)^5 in the polar form <BR>\n" );
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document.write( "r = sqrt(2^2+3^2) = sqrt(13)<BR>\n" );
document.write( "theta = tan^-1(-3/2) = 303.69 degrees<BR>\n" );
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document.write( "(-2+3i)^5 = 13^(5/2)[cos(303.69)+isin(303.69)<BR>\n" );
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document.write( "and in cartesian form<BR>\n" );
document.write( "(-2+3i)^5 = x + yi<BR>\n" );
document.write( "x = 13^(5/2)*cos(303.69) = 338<BR>\n" );
document.write( "y = 13^(5/2)*isin(303.69) = -507i<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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