document.write( "Question 462728: Find a number whose double is 45 greater than its half? \n" ); document.write( "
Algebra.Com's Answer #317151 by robertb(5830) You can put this solution on YOUR website! 2x = x/2 + 45\r \n" ); document.write( "\n" ); document.write( "==> 2x - x/2 = 45\r \n" ); document.write( "\n" ); document.write( "<==> (3x)/2 = 45\r \n" ); document.write( "\n" ); document.write( "==> 3x = 90\r \n" ); document.write( "\n" ); document.write( "==> x = 90/3 = 30, the unknown number. \n" ); document.write( " |