document.write( "Question 462600: Please give step by step instructions on solving this problem...
\n" ); document.write( "\"3%5Ex+=+8%5E%28x-8%29\"
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Algebra.Com's Answer #317146 by math-vortex(648)\"\" \"About 
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Please give step by step instructions on solving this problem...
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\n" ); document.write( "There are several ways to solve this problem Here is a method that I like. Warning: this problem has LOTS of algebra twists and turns!
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\n" ); document.write( "Remember that the logarithm function is the inverse of the exponential function. This means that I can rewrite any exponential equation as a logarithmic equation.
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\n" ); document.write( "We are given
\n" ); document.write( "\"3%5Ex+=+8%5E%28x-8%29\"
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\n" ); document.write( "Since these to expressions are equivalent, their natural logarithms are equivalent. So,
\n" ); document.write( "\"ln%283%5Ex%29=ln%288%5E%28x-8%29%29\"
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\n" ); document.write( "Using the power property for the logarithms, we have
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\n" ); document.write( "Now we expand the right side of the equation.
\n" ); document.write( "\"ln%283%29%2Fln%288%29=x%2Fx-8%2Fx=1-8%2Fx\"
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\n" ); document.write( "Solve for x.
\n" ); document.write( "\"ln%283%29%2Fln%288%29-1=-8%2Fx\"
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\n" ); document.write( "\"ln%283%29%2Fln%288%29-ln%288%29%2Fln%288%29=-8%2Fx\"
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\n" ); document.write( "\"ln%283%29-ln%288%29%2Fln%288%29=-8%2Fx\"
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\n" ); document.write( "\"%28ln%283%29-ln%288%29%29%2Fln%288%29=-8%2Fx\"
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\n" ); document.write( "Apply the division property for subtracting logarithms.
\n" ); document.write( "\"ln%283%2F8%29%2Fln%288%29=-8%2Fx\"
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\n" ); document.write( "\"x=%28-8%2Aln%288%29%29%2F%28ln%283%2F8%29%29\"
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\n" ); document.write( "hope this helps!
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\n" ); document.write( "Ms.Figgy
\n" ); document.write( "math.in.the.vortex
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