document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=457662>Question 457662</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose that x liters of pure acid (100% acid) are added to 280 liters of a 25% acid solution. How many liters of pure acid should be added to produce a mixture that is 51% acid? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #317127 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=317127\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+280(.25)=.51(280+x)<BR>\n" );
document.write( "x+70=142.8+.51x<BR>\n" );
document.write( ".49x=72.8<BR>\n" );
document.write( "x=72.8/.49=148.57<BR>\n" );
document.write( "You need 148.57 liters of pure acid for your mix.. </SPAN>\n" );
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