document.write( "Question 462652: In 1990 the life expectancy of males in a certain country was 65.4 years. In 1996, it was 69.0 years. Let E represent the life expectancy in year t and let t represent the number of years since 1990. The linear function that fits the data is E(t)=_t+_ \n" ); document.write( "

Algebra.Com's Answer #317118 by josmiceli(19441) $\"\"$ $\"About$

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Plot years on the horizontal and
\n" ); document.write( "life expectancy on the vertical.
\n" ); document.write( "Using the point-slope formula,
\n" ); document.write( " $\"+%28+E+-+65.4+%29+%2F+%28+t+-+0+%29+=+%28+69+-+65.4+%29+%2F+%28+6+-+0+%29+\"$
\n" ); document.write( "Multiply both sides by $\"+6t+\"$
\n" ); document.write( " $\"+6%2A%28+E+-+65.4+%29+=+3.6%2At+\"$
\n" ); document.write( " $\"+6E+-+392.4+=+3.6t++\"$
\n" ); document.write( " $\"+6E+=+3.6t+%2B+392.4+\"$
\n" ); document.write( " $\"+E+=+.6t+%2B+65.4+\"$
\n" ); document.write( "check answer:
\n" ); document.write( "1990:
\n" ); document.write( " $\"+65.4+=+.6t+%2B+65.4+\"$
\n" ); document.write( " $\"+.6t+=+0+\"$
\n" ); document.write( " $\"+t+=+0+\"$ (or 1990)
\n" ); document.write( "1996:
\n" ); document.write( " $\"+69+=+.6t+%2B+65.4+\"$
\n" ); document.write( " $\"+.6t+=+3.6+\"$
\n" ); document.write( " $\"+t+=+6+\"$ (or 1996)
\n" ); document.write( "OK \n" ); document.write( "

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