document.write( "Question 456117: You have one type of candy that sells for $2.00/lb and another type of candy that sells for $8.00/lb. You would like to have 30 lbs of a candy mixture that sells for $3.90/lb. How much of each candy will you need to obtain the desired mixture?\r
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document.write( "You will need
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document.write( " ? lbs of the cheaper candy
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document.write( "and
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document.write( " ? lbs of the expensive candy. \n" );
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Algebra.Com's Answer #317114 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! m+n=30 \n" ); document.write( "2m+8n=30(3.90)=117 \n" ); document.write( "2m+2n=60 \n" ); document.write( "6n=57 \n" ); document.write( "n=57/6 \n" ); document.write( "m=123/6 \n" ); document.write( "You need 123/6 lbs. of $2 candy and 57/6 lbs. of $8 candy for your mix.. \n" ); document.write( " \n" ); document.write( " |