document.write( "Question 456117: You have one type of candy that sells for $2.00/lb and another type of candy that sells for $8.00/lb. You would like to have 30 lbs of a candy mixture that sells for $3.90/lb. How much of each candy will you need to obtain the desired mixture?\r
\n" ); document.write( "\n" ); document.write( "You will need
\n" ); document.write( " ? lbs of the cheaper candy
\n" ); document.write( "and
\n" ); document.write( " ? lbs of the expensive candy.
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Algebra.Com's Answer #317114 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
m+n=30
\n" ); document.write( "2m+8n=30(3.90)=117
\n" ); document.write( "2m+2n=60
\n" ); document.write( "6n=57
\n" ); document.write( "n=57/6
\n" ); document.write( "m=123/6
\n" ); document.write( "You need 123/6 lbs. of $2 candy and 57/6 lbs. of $8 candy for your mix..
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