document.write( "Question 462476: A boat can go 63 mph in still water. It takes as long to go 120 miles upstream as it does to go 150 miles downstream. What is the current? \n" ); document.write( "
Algebra.Com's Answer #317063 by rwm(914)\"\" \"About 
You can put this solution on YOUR website!
(63+x)*t=150
\n" ); document.write( "t=150/(63+x)
\n" ); document.write( "(63-x)*t=120
\n" ); document.write( "t=120/(63-x)
\n" ); document.write( "150/(63+x)=120/(63-x)
\n" ); document.write( "120*(63+x)=150*(63-x)
\n" ); document.write( "x=7 mph current
\n" ); document.write( "BTW t=15/7
\n" ); document.write( "(63+7)*15/7=150
\n" ); document.write( "10*15=150
\n" ); document.write( "ok
\n" ); document.write( "(63-7)*15/7=120
\n" ); document.write( "56/7*15=120
\n" ); document.write( "8*15=120
\n" ); document.write( "ok\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
\n" );