document.write( "Question 462479: leg1: x+2 leg2: x and the hypotenuse is square root of 10. how to find x using the pythagorean theorem?. \n" ); document.write( "
Algebra.Com's Answer #317044 by nerdybill(7384)\"\" \"About 
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leg1: x+2 leg2: x and the hypotenuse is square root of 10. how to find x using the pythagorean theorem?.
\n" ); document.write( ".
\n" ); document.write( "Pythagorean theorem says:
\n" ); document.write( "(leg1)^2 + (leg2)^2 = (hypotenuse)^2
\n" ); document.write( "plug in what was given:
\n" ); document.write( "(x+2)^2 + x^2 = (sqrt(10))^2
\n" ); document.write( "(x+2)^2 + x^2 = 10
\n" ); document.write( "(x+2)(x+2) + x^2 = 10
\n" ); document.write( "x^2+4x+4 + x^2 = 10
\n" ); document.write( "2x^2+4x+4 = 10
\n" ); document.write( "2x^2+4x-6 = 0
\n" ); document.write( "x^2+2x-3 = 0
\n" ); document.write( "factoring:
\n" ); document.write( "(x+3)(x-1) = 0
\n" ); document.write( "x = {-3,1}
\n" ); document.write( "throw out the negative solution (extraneous) leaving:
\n" ); document.write( "x = 1 \n" ); document.write( "
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