document.write( "Question 462475: PLEASE HELP ME, I posted this problem once, and no one responded, can you help me?
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document.write( "which pair has equally likley outcomes? list the letters of the two choices below which have equal probabilities of success.
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document.write( "a)drawing a red seven out of a standard 52 card deck given its not a face card or an ace.
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document.write( "b)drawing a five out of a standard 52 card deck given its not a face card or an ace.
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document.write( "c)rolling a sum of 4 on two fair six sided dice.
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document.write( "d)rolling a sum of 5 on two fair six sided dice.
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document.write( "e)rolling a sum of 7 on two fair six sided dice. \n" );
document.write( "
Algebra.Com's Answer #317041 by math-vortex(648) You can put this solution on YOUR website! -------------------------- \n" ); document.write( "a)drawing a red seven out of a standard 52 card deck given its not a face card or an ace. \n" ); document.write( "-------------------------- \n" ); document.write( "P(red 7|not face or ace) = P(not face or ace AND red 7) / P(not face or ace) \n" ); document.write( ". \n" ); document.write( "P(red seven AND not face or ace) = 2/52 because there are 2 red seven cards (red-diamond and red-heart) in the deck of 52 cards. \n" ); document.write( ". \n" ); document.write( "P(not face or ace) = 36/52 because there are 9*4=36 non-face or non-ace cards (2 through 10 of every suit) in a deck of 52 cards. \n" ); document.write( ". \n" ); document.write( "P(red 7|not face or ace) = (2/52) / (36/52) = 2/36 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "-------------------------- \n" ); document.write( "b)drawing a five out of a standard 52 card deck given its not a face card or an ace. \n" ); document.write( "-------------------------- \n" ); document.write( "P(five|not face or ace) = P(not face or ace AND red 7) / P(not face or ace) \n" ); document.write( ". \n" ); document.write( "P(five AND not face or ace) = 4/52 because there are 4 fives (five-diamond, -heart, -club, and -spade) in the deck of 52 cards. \n" ); document.write( ". \n" ); document.write( "P(not face or ace) = 36/52 because there are 9*4=36 non-face or non-ace cards (2 through 10 of every suit) in a deck of 52 cards. \n" ); document.write( ". \n" ); document.write( "P(five|not face or ace) = (4/52) / (36/52) = 4/36 \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "more coming soon!!! \n" ); document.write( "-------------------------- \n" ); document.write( "c)rolling a sum of 4 on two fair six sided dice. \n" ); document.write( "-------------------------- \n" ); document.write( "A good way to solve die rolling problems is to build a grid of possible dice sums. \n" ); document.write( "+ 1 2 3 4 5 6 \n" ); document.write( "------------------- \n" ); document.write( "1| 2 3 4 5 6 7 \n" ); document.write( "2| 3 4 5 6 7 8 \n" ); document.write( "3| 4 5 6 7 8 9 \n" ); document.write( "4| 5 6 7 8 9 10 \n" ); document.write( "5| 6 7 8 9 10 11 \n" ); document.write( "6| 7 8 9 10 11 12 \n" ); document.write( ". \n" ); document.write( "(hopefully, this lines up nicely in your browser (o: \n" ); document.write( "Now we can see count easily. \n" ); document.write( ". \n" ); document.write( "Events: \n" ); document.write( "E = rolling a sum of 4 \n" ); document.write( "S = rolling any sum\r \n" ); document.write( "\n" ); document.write( "There are 3 ways to roll a sum of 4 [(1+3, 3+1, 2+2)] and 36 ways to roll ANY sum. So the probability of our event is\r \n" ); document.write( "\n" ); document.write( "P(E) = n(E) / n(S) = 3/36\r \n" ); document.write( "\n" ); document.write( "Problems (d) and (e) use identical reasoning to (c). They will be good practice for you. Finish the problem by finding the two events with equal probabilities. \n" ); document.write( ". \n" ); document.write( "hope this helps! Feel free to contact me at math.in.the.vortex@gmail.com. \n" ); document.write( ". \n" ); document.write( "Ms.Figgy \n" ); document.write( "math.in.the.vortex \n" ); document.write( " \n" ); document.write( " |