document.write( "Question 47914: I'm having a hard time with this problem. I'm not sure if I'm doing this right.
\n" ); document.write( "It says solve the system by the elimination method
\n" ); document.write( "7x+5y=42
\n" ); document.write( "4x-3y=24
\n" ); document.write( "doing this I came up with this 28x+20y=168
\n" ); document.write( " 28x-21y=168
\n" ); document.write( "some how I end up with -1. I'm trying to cancell out the x but the 168 is bothering me, it doesnt look right. Please help me \n" ); document.write( "
Algebra.Com's Answer #31704 by 1980.vikas(7)\"\" \"About 
You can put this solution on YOUR website!
first of all i want to say in elimination method we have to eliminate x or y in any of the equation.
\n" ); document.write( "let us eliminate x from 4x - 3y= 24, we get
\n" ); document.write( "x = 6 + (3/4)y ....................(i)\r
\n" ); document.write( "\n" ); document.write( "now put this value of x in the other equation i.e. 7x + 5y = 42
\n" ); document.write( "=> 7 * (6 + (3/4)y)+ 5y = 42
\n" ); document.write( "=> 42 + (21/4)y + 5y = 42
\n" ); document.write( "=> (21/4)y + 5y = 0
\n" ); document.write( "=> y[(21/4) + 5] = 0
\n" ); document.write( "=> y = 0\r
\n" ); document.write( "\n" ); document.write( "Putting the value of y in the equation (i), we get:
\n" ); document.write( "x = 6
\n" ); document.write( " \n" ); document.write( "
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