document.write( "Question 462379: Two trains are 330 miles apart, and their speeds differ by 20 mph. They travel toward each other and meet in 3 hrs. Find the speed of each train. \r
\n" ); document.write( "\n" ); document.write( "I'm having trouble putting this problem into an equation.
\n" ); document.write( "It's different from the other travel/distance questions i've had.
\n" ); document.write( "I understand if i'm given the mph for each train but i don't know how to find it in this problem. \r
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Algebra.Com's Answer #316992 by MathLover1(20855)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "given data: \"1st\"\"+train+\"\r
\n" ); document.write( "\n" ); document.write( "distance: \"x-miles+\" miles ; time \"t=+3+h\" ; rate \"r1=+x%2F3h\"\r
\n" ); document.write( "\n" ); document.write( "\"2nd\"\"+train\" :\r
\n" ); document.write( "\n" ); document.write( "distance: \"%28330-x%29+miles\" ; time \"t=+3+h\" ; rate \"r2=+%28330-x%29%2F3h\"\r
\n" ); document.write( "\n" ); document.write( "rate1 - rate2 \r
\n" ); document.write( "\n" ); document.write( "\"r1-r2=+20\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3h-%28330-x%29%2F3h+=+20\"\r
\n" ); document.write( "\n" ); document.write( "\"%28x%2F3%29+-+%28110-%28x%2F3%29%29+=+20\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F3%29x+=+20+%2B+110\"\r
\n" ); document.write( "\n" ); document.write( "\"%282%2F3%29x+=+130\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+%283%2F2%29130\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+195+mil\"...... distance traveled by 1st train\r
\n" ); document.write( "\n" ); document.write( "\"speed\" of first train is \"v1+=+195%2F3+=+65+mph\"\r
\n" ); document.write( "\n" ); document.write( "\"speed\"of second train is \"v2+=+%28330-195%29%2F3+=+45+mph\"
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