document.write( "Question 462331: What are the foci of the ellipse given by the equation [((x-2)^2)/36]+[((y-8)^2)/144]=1?\r
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document.write( "Please explain! I am having trouble with this. \r
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document.write( "Thank you! \n" );
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Algebra.Com's Answer #316949 by graphmatics(170)![]() ![]() You can put this solution on YOUR website! ((x-2)^2)/36+((y-8)^2)/144=1\r \n" ); document.write( "\n" ); document.write( "From the general equation \n" ); document.write( "[((x-h)^2)/a^2]+[((y-k)^2)/b^2]=1 we know that the center of the ellipse is at (h,k). So for our ellipse equation the center of the ellipse is at (2,8).\r \n" ); document.write( "\n" ); document.write( "c is the distance from the center to a focus point. The expression for c (when b > a) is\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "So for our ellipse \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The expression for the foci of a general ellipse is \n" ); document.write( "Foci: (c+h, k) (-c+h, k) \n" ); document.write( "So for our ellipse the foci are (10.3923+2, 8) (-10.3923+2, 8) \n" ); document.write( "(12.3923, 8) (-8.3923, 8)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |