document.write( "Question 462331: What are the foci of the ellipse given by the equation [((x-2)^2)/36]+[((y-8)^2)/144]=1?\r
\n" ); document.write( "\n" ); document.write( "Please explain! I am having trouble with this. \r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #316949 by graphmatics(170)\"\" \"About 
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((x-2)^2)/36+((y-8)^2)/144=1\r
\n" ); document.write( "\n" ); document.write( "From the general equation
\n" ); document.write( "[((x-h)^2)/a^2]+[((y-k)^2)/b^2]=1 we know that the center of the ellipse is at (h,k). So for our ellipse equation the center of the ellipse is at (2,8).\r
\n" ); document.write( "\n" ); document.write( "c is the distance from the center to a focus point. The expression for c (when b > a) is\r
\n" ); document.write( "\n" ); document.write( "\"c+=+sqrt%28+b%5E2-a%5E2+%29+\"
\n" ); document.write( "So for our ellipse
\n" ); document.write( "\"c+=+sqrt%28+12%5E2-6%5E2+%29+\"
\n" ); document.write( "\"c+=+sqrt%28+144-36+%29+\"
\n" ); document.write( "\"c+=+sqrt%28+108+%29+\"
\n" ); document.write( "\"c+=+10.3923+\"
\n" ); document.write( "The expression for the foci of a general ellipse is
\n" ); document.write( "Foci: (c+h, k) (-c+h, k)
\n" ); document.write( "So for our ellipse the foci are (10.3923+2, 8) (-10.3923+2, 8)
\n" ); document.write( "(12.3923, 8) (-8.3923, 8)\r
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