document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462174>Question 462174</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a minor league baseball team plays 98 games in a season. if the team won 14 more than three times as many games they lost, how many wins and losses did the team have? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316886 by </B><A HREF=/tutors/aboutme.mpl?userid=graphmatics><B>graphmatics(170)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=graphmatics><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=graphmatics><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316886\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the number of games the team won. Let y be the number of games the team lost. Then x+y = 98<BR>\n" );
document.write( "Because the team won 14 more than three times as many games they lost<BR>\n" );
document.write( "x = 14 + 3*y\r<BR>\n" );
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document.write( "Substitute the value of x from the second equation into the first equation to get\r<BR>\n" );
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document.write( "(14 + 3*y) + y = 98<BR>\n" );
document.write( "4*y = 98 -14<BR>\n" );
document.write( "4*y = 84<BR>\n" );
document.write( "y = 84/4<BR>\n" );
document.write( "y = 21\r<BR>\n" );
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document.write( "so to get x we substitute y = 21 into the first equation to get<BR>\n" );
document.write( "x + 21 = 98<BR>\n" );
document.write( "x = 98 -21<BR>\n" );
document.write( "x = 77   </SPAN>\n" );
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