document.write( "Question 462173: y^4+24y^2-25=0 Solve the polynomial equation by indicating first set of solutions and the second set. \n" ); document.write( "
Algebra.Com's Answer #316883 by algebrahouse.com(1659)\"\" \"About 
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y^4 + 24y^2 - 25 = 0
\n" ); document.write( "(y² + 25)(y² - 1) = 0 {factored into two binomials}
\n" ); document.write( "y² + 25 = 0 or y² - 1 = 0 {set each factor equal to 0}
\n" ); document.write( "y² = -25 or y² = 1 {subtracted 25 and added 1 respectively}
\n" ); document.write( "y = ±√-25 or y = ±√1 {took square root of both sides in each equation}
\n" ); document.write( "y = ±√-1 √25 or y = ±1 {broke -25 into 25 and -1 and evaluated √1 to be 1}
\n" ); document.write( "y = ±5i or y = ±1 {evaluated √-1 to be i}
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