document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462169>Question 462169</A>: <I><SPAN STYLE=\"word-break: break-all;\"> subtract, simplify if possible\r<BR>\n" );
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document.write( "7/5x^2-5x  - 3/5x-5\r<BR>\n" );
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document.write( "the dashes are indicating fractions, and ^ means to the power of </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316880 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 7/(5x² - 5x) - 3/(5x - 5)<BR>\n" );
document.write( "7/[5x(x - 1)] - 3/[5(x - 1)] {factored denominators<BR>\n" );
document.write( "7/[5x(x - 1)] - 3x/[5x(x - 1)] {got common denominator of 5x(x - 1)}\r<BR>\n" );
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document.write( "7 - 3x<BR>\n" );
document.write( "-------- {combined numerators and put over common denominator}<BR>\n" );
document.write( "5x(x - 1)<BR>\n" );
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