document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462101>Question 462101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A driver of the car took a day trip around the California coast line driving at two different speed. He drove 70 miles at a slower speed and 300 miles at a speed 40 miles hour faster. If the time spent during the faster speed was twice that spent at a slower speed, find the two speeds during the trip. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316858 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316858\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let slower speed = x ===> distance = 70<BR>\n" );
document.write( "faster speed= x+40 ====> distance = 300 miles\r<BR>\n" );
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document.write( "t=d/r\r<BR>\n" );
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document.write( "2(70/x) = (300/(x+40))<BR>\n" );
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document.write( "cross multiply\r<BR>\n" );
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document.write( "140(x+40)=300x<BR>\n" );
document.write( "140x+5600=300x<BR>\n" );
document.write( "160x=5600<BR>\n" );
document.write( "x=35 mph\r<BR>\n" );
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document.write( "faster speed = 75 mph </SPAN>\n" );
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