document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462140>Question 462140</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -11-(x+30)=-41-2(5x-18). How do I solve this. Could someone show me the steps so that I can understand this problem, thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316855 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -11 - (x + 30) = -41 - 2(5x - 18)<BR>\n" );
document.write( "-11 - x - 30 = -41 - 10x + 36 {used distributive property}<BR>\n" );
document.write( "-x - 41 = -10x - 5 {combined like terms}<BR>\n" );
document.write( "9x - 41 = -5 {added 10x to both sides}<BR>\n" );
document.write( "9x = 36 {added 41 to both sides}<BR>\n" );
document.write( "x = 4 {divided both sides by 9}<BR>\n" );
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