document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462103>Question 462103</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A driver of the car took a day trip around the California coast line driving at two different speed. He drove 70 miles at a slower speed and 300 miles at a speed 40 miles per hour faster. If the time spent during the faster speed was twice that spent at a slower speed, find the two speeds during the trip. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316824 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316824\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A driver of the car took a day trip around the California coast line driving at two different speed. He drove 70 miles at a slower speed and 300 miles at a speed 40 miles per hour faster. If the time spent during the faster speed was twice that spent at a slower speed, find the two speeds during the trip.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "let x=slower speed<BR>\n" );
document.write( "x+40 = faster speed<BR>\n" );
document.write( "time traveled =distance/speed<BR>\n" );
document.write( "2*70/x=300/(x+40)<BR>\n" );
document.write( "140/x=300/(x+40)<BR>\n" );
document.write( "300x=140x+40*140<BR>\n" );
document.write( "160x=40*140<BR>\n" );
document.write( "x=40*140/160=35 mph<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "slower speed = 35 mph<BR>\n" );
document.write( "faster speed =x+40=75 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );