document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462067>Question 462067</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I having a lot of trouble figuring out how to do this problem,\r<BR>\n" );
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document.write( "+ solve the system of equations by using the substitution method.\r<BR>\n" );
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document.write( "x + 2y = -12<BR>\n" );
document.write( "x= -5y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316796 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316796\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + 2y = -12<BR>\n" );
document.write( "x = -5y\r<BR>\n" );
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document.write( "x + 2y = -12 {top equation}<BR>\n" );
document.write( "-5y + 2y = -12 {substituted -5y, in for x, into the top equation}<BR>\n" );
document.write( "-3y = -12 {combined like terms}<BR>\n" );
document.write( "y = 4 {divided both sides by -3}\r<BR>\n" );
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document.write( "x = -5y {original bottom equation}<BR>\n" );
document.write( "x = -5(4) {substituted 4, in for y, into x = -5y}<BR>\n" );
document.write( "x = -20 {multiplied}\r<BR>\n" );
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document.write( "x = -20 and y = 4<BR>\n" );
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