document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=462023>Question 462023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am resubmitting this problem once again, I entered it incorrectly the second time.  The problem reads:\r<BR>\n" );
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document.write( "A picture frame measures 12cm by 20cm and 128cm^2 of the picture shows. Find the width of the frame\r<BR>\n" );
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document.write( "Thanks, again </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316772 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316772\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Assuming the width of the frame is the same all the way round:\r<BR>\n" );
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document.write( "(20-x)(12-x) =  128\r<BR>\n" );
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document.write( "240-12x-20x+x^2 = 128\r<BR>\n" );
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document.write( "x^2 -32x+240 = 128<BR>\n" );
document.write( "x^2-32x+112 = 0<BR>\n" );
document.write( "x-16)^2 - 144 = 0\r<BR>\n" );
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document.write( "x = sqrt 144 + 16\r<BR>\n" );
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document.write( "x = (-12) + 16 (can't be +12 as the dimensions are only 20cm by 12cm)\r<BR>\n" );
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document.write( "x= 4<BR>\n" );
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