document.write( "Question 462021: The value of 83 coins consisting of dimes and nickles is $5.75. Find the number of nickles \n" ); document.write( "
Algebra.Com's Answer #316769 by katealdridge(100)\"\" \"About 
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This is a system of equations. Let d=the number of dimes and n=the number of nickels.
\n" ); document.write( "\".10d%2B.05n=5.75\"
\n" ); document.write( "\"d%2Bn=83\" Solve this equation for d.
\n" ); document.write( "\"d=83-n\" Now take 83-n and substitute it into the first equation for d.
\n" ); document.write( "\".10%2883-n%29%2B.05n=5.75\" Simplify and solve.
\n" ); document.write( "\"8.3-.10n%2B.05n=5.75\"
\n" ); document.write( "\"8.3-.05n=5.75\"
\n" ); document.write( "\"-.05n=-2.55\"
\n" ); document.write( "\"n=51\" 51 nickels. Since there are 83 coins altogether, then there must be 32 dimes.
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