document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=47879>Question 47879</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Ok, in conjunction of question 47866, using this formula below:<BR>\n" );
document.write( " log b a = <BR>\n" );
document.write( "log a<BR>\n" );
document.write( " _____<BR>\n" );
document.write( " log b\r<BR>\n" );
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document.write( "Using this formula, find log 2 1000. Round your answer to the hundredth's place.\r<BR>\n" );
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document.write( "(NOTE: the b in log b a is small as well as the 2 in log 2 1000) Hope that makes sense. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #31674 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=31674\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find log 2 1000\r<BR>\n" );
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document.write( "=(log 1000)/(log 2)\r<BR>\n" );
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document.write( "=3/0.30103000\r<BR>\n" );
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document.write( "=9.96578428...\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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