document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=461933>Question 461933</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the average of three distinct positive intergers is 4 what is the greatest possible value for one of those integers \r<BR>\n" );
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document.write( "a) 5<BR>\n" );
document.write( "b) 6<BR>\n" );
document.write( "c) 9<BR>\n" );
document.write( "d) 11<BR>\n" );
document.write( "e) 12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316701 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316701\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c) 9.\r<BR>\n" );
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document.write( "Since the terms of the sum are all positive integers, then the least value any of the terms can take is 1.  The second least positive integral value one of the remaining terms can take is 2.  (Remember the value of the next term is distinct from the first, and hence higher.)  The value of the remaining term must then be maximal, which is 12 - 1 - 2 = 9. </SPAN>\n" );
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