document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=461906>Question 461906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if y=2x+3 and x*y<0 then what is the range of x? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316696 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316696\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If y = 2x + 3, then solve the inequality x(2x + 3) <0.\r<BR>\n" );
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document.write( "The critical numbers are 0, -1.5.<BR>\n" );
document.write( "For x < -1.5, x(2x + 3) > 0.<BR>\n" );
document.write( "For -1.5 < x < 0, x(2x + 3) < 0.<BR>\n" );
document.write( "For x > 0, x(2x + 3) > 0.<BR>\n" );
document.write( "Therefore the range of x is the interval(-1.5, 0). </SPAN>\n" );
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