document.write( "Question 455518: how many quarts of pure antifreeze must be added to 6 quarts of a 20% antifreeze solution to obtain a 50% antifreeze solution? \n" ); document.write( "

Algebra.Com's Answer #316632 by jorel1380(3719) $\"\"$ $\"About$

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6(.20)+m=.5(6+m)
\n" ); document.write( "1.2+m=3+.5m
\n" ); document.write( ".5m=1.8
\n" ); document.write( "m=1.8/.5=3.6
\n" ); document.write( "3.6 qts. of pure antifreeze must be added to the solution.
\n" ); document.write( "1.2+3.6=.5(6+3.6)
\n" ); document.write( "4.8=4.8 \n" ); document.write( "

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