document.write( "Question 47875: Solve the equation. Thanks\r
\n" ); document.write( "\n" ); document.write( " $\"Photobucket$ \n" ); document.write( "

Algebra.Com's Answer #31663 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"sqrt%283x+%2B+10%29+=+5+-+2x\"$
\n" ); document.write( " $\"3x+%2B+10+=+25+-+20x+%2B+4x%5E2\"$
\n" ); document.write( " $\"0+=+4x%5E2+-+23x+%2B+15\"$
\n" ); document.write( " $\"0+=+4x%5E2+-+3x+-+20x+%2B+15\"$
\n" ); document.write( " $\"0+=+%284x%5E2+-+3x%29+%2B+%28-20x+%2B+15%29\"$
\n" ); document.write( " $\"0+=+x%284x+-+3%29+-+5%284x+-+3%29\"$
\n" ); document.write( " $\"0+=+%28x+-+5%29%284x+-+3%29\"$
\n" ); document.write( "x - 5 = 0
\n" ); document.write( "x = 5
\n" ); document.write( "and
\n" ); document.write( "4x - 3 = 0
\n" ); document.write( "4x = 3
\n" ); document.write( "x = 3/4
\n" ); document.write( "Check:
\n" ); document.write( "x = 5 will not work because the square root of a real number will not equal a positive value. Answer: x = 3/4
\n" ); document.write( " $\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2Csqrt%283x+%2B+10%29%2C5+-+2x%29\"$ \n" ); document.write( "

\n" );