document.write( "Question 461758: find the center-radius form of the equation of a circle with center (4,8) and tangent to the X-axis.
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Algebra.Com's Answer #316588 by Gogonati(855)\"\" \"About 
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The standard form of the equation of the circle is \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Since our circle is tangent to the x-axis its radius will be perpendicular to the \r
\n" ); document.write( "\n" ); document.write( "the x-axis at the point (4, 0), and its radius will be:\r
\n" ); document.write( "\n" ); document.write( "\"r%5E2=%284-4%29%5E2%2B%280-8%29%5E2=64\", and the equation of the circle is:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-4%29%5E2%2B%28y-8%29%5E2=64\".
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