document.write( "Question 461640: jim is 5 years older than cindy.4 years ago, the sum of their ages was 21.find each of their ages now \n" ); document.write( "
Algebra.Com's Answer #316538 by simranb(63)\"\" \"About 
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Let cindy's age be x
\n" ); document.write( "Then jim's age= x+5
\n" ); document.write( "Cindy's age 4 years ago=x-4
\n" ); document.write( "Then jim's age 4 years ago = x+5-4
\n" ); document.write( " = x+1
\n" ); document.write( "Sum of their ages 4 years ago =21
\n" ); document.write( "Equation
\n" ); document.write( "x-4+x+1=21
\n" ); document.write( "2x-3=21
\n" ); document.write( "2x-3=21
\n" ); document.write( "2x=21+3
\n" ); document.write( "2x=24
\n" ); document.write( "x=24/2
\n" ); document.write( "x=12
\n" ); document.write( "Cindy's age=12yrs
\n" ); document.write( "Jim's Age = 12+5
\n" ); document.write( " = 17yrs
\n" ); document.write( "Cheers!
\n" ); document.write( "Hope this helps!\r
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