document.write( "Question 47861: Sketch one period of the following trigonometric graphs:\r
\n" ); document.write( "\n" ); document.write( "a.) cos^2(x)
\n" ); document.write( "b.) |sin x|
\n" ); document.write( "c.) y= 3 cos (4x) - 1\r
\n" ); document.write( "\n" ); document.write( "I am not certain about my answers...can someone show me how it will look? thanks i really need the help.
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Algebra.Com's Answer #31652 by Nate(3500)\"\" \"About 
You can put this solution on YOUR website!
a.) f(x) = cos^2(x) = cos(x)^2
\n" ); document.write( "This means that there are no negative values, but there are zero values.
\n" ); document.write( "\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2Ccos%28x%29%5E2%29\"
\n" ); document.write( "Period: \"pi\"
\n" ); document.write( "b.) f(x) = |sin(x)| = sqrt(sin(x)^2)
\n" ); document.write( "This means that there are no negative values, but there are zero values once again.
\n" ); document.write( "\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2Csqrt%28sin%28x%29%5E2%29%29\"
\n" ); document.write( "Period: \"pi\"
\n" ); document.write( "c.) f(x) = 3*cos(4x) - 1
\n" ); document.write( "Period: \"2%28pi%29%2Fa\" where \"a\" is the coefficient = \"2%28pi%29%2F4+=+%28pi%29%2F2\"
\n" ); document.write( "\"graph%28600%2C600%2C-10%2C10%2C-10%2C10%2C3%2Acos%284x%29+-+1%2C-1%29\"
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