document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=461553>Question 461553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help!!!!!!!!!!!<BR>\n" );
document.write( "simplify as much as possible, showing all factoring, canceling, and steps for finding the lowest common denominator. assume that no denominator is zero.\r<BR>\n" );
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document.write( "(3/c^2+4) + (a/c^2+4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316495 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316495\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3/(cē + 4) + a/(cē + 4)\r<BR>\n" );
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document.write( "3 + a<BR>\n" );
document.write( "------- {combined the numerators over the common denominator}<BR>\n" );
document.write( "cē + 4\r<BR>\n" );
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