document.write( "Question 461537: the sum of the present ages of Eric and his father is 58 years. In 10 years, his father will be twice as old as Eric will be at that time, Find their present ages \n" ); document.write( "
Algebra.Com's Answer #316485 by algebrahouse.com(1659)\"\" \"About 
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the sum of the present ages of Eric and his father is 58 years. In 10 years, his father will be twice as old as Eric will be at that time, Find their present ages\r
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\n" ); document.write( "\n" ); document.write( "x = Eric's age now
\n" ); document.write( "58 - x = father's age now {sum of present ages is 58}\r
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\n" ); document.write( "\n" ); document.write( "x + 10 = Eric's age in 10 years {added 10 onto current age}
\n" ); document.write( "68 - x = father's age in 10 years {added 10 onto current age}\r
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\n" ); document.write( "\n" ); document.write( "68 - x = 2(x + 10) {in ten years, the father will be twice Eric}
\n" ); document.write( "68 - x = 2x + 20 {used distributive property}
\n" ); document.write( "68 = 3x + 20 {added x to both sides}
\n" ); document.write( "3x = 48 {subtracted 20 from both sides}
\n" ); document.write( "x = 16 {divided both sides by 3}
\n" ); document.write( "58 - x = 42 {substituted 16, in for x, into 58 - x}\r
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\n" ); document.write( "\n" ); document.write( "Eric is 16
\n" ); document.write( "father is 42
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