document.write( "Question 461511: In January, your ceramics class begins with 12 students. In every month after January, three new students join and one student drops out.
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document.write( "(a) Write a linear equation to model the situation.
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document.write( "(b) Graph a model
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document.write( "(c) Predict the size of your ceramics class in May and June.\r
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document.write( "Need help with a and c and then will try my hand at the graphing.
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Algebra.Com's Answer #316482 by graphmatics(170) You can put this solution on YOUR website! Let y be the number of students in a given month. Let x be the number of months with x = 1 being January. \n" ); document.write( "then (x-1)*3 is the number of new students and (x-1) is the number of student drop outs. \n" ); document.write( "Then\r \n" ); document.write( "\n" ); document.write( "y = 12 + (x-1)*3 - (x-1) \n" ); document.write( "Lets simplify this as y = m*x+b \n" ); document.write( "So \n" ); document.write( "y = 12 + (x-1)*3 - (x-1) \n" ); document.write( "y = 12 + 3*x -3 -x +1 \n" ); document.write( "y = 2*x + 10\r \n" ); document.write( "\n" ); document.write( "Here is the graph of the linear equation that models the situation\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If in January x = 1 then in May x = 5. So the expression of the Linear Equation when x = 5 is\r \n" ); document.write( "\n" ); document.write( "y = 2*5 + 10 \n" ); document.write( "y = 20 \n" ); document.write( "and in June x = 6 so \n" ); document.write( "y = 22 \n" ); document.write( " |