document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=461286>Question 461286</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose you have a right triangle whose hypotenuse has length 8. One of the other sides has length 5. Then the smaller of the two acute angles is  degrees and the larger acute angle is  degrees \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316382 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316382\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "The third side of the triangle is <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \sqrt{39}\"> which is a little more than 6.  Hence the small angle is opposite the side that measures 5.\r<BR>\n" );
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document.write( "The small angle is then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \alpha\ =\ \sin^{-1}\left(\frac{5}{8}\right)\">\r<BR>\n" );
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document.write( "The larger angle is then <IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \beta\ =\ 90^\circ\ -\ \alpha\">\r<BR>\n" );
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document.write( "Make sure you set your calculator for degrees instead of radians.\r<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi} + 1 = 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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