document.write( "Question 461263: the numbers are 1,2,3,4, and 5 but not in that order
\n" ); document.write( "the first digit plus the second digit is equal to the third digit
\n" ); document.write( "the second digit is two times the first digit
\n" ); document.write( "the second digit is half the fourth digit and
\n" ); document.write( "the fifth digit is the sum of the first and fourth digits
\n" ); document.write( "

Algebra.Com's Answer #316374 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Oh yes they are in that order.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Given the digits 1, 2, 3, 4, and 5:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If the second digit is two times the first, then the second digit must be an even number. Only 2 and 4 are even from the list of givens, hence the first two digits are either 12 or 24.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Consider the first condition: the sum of the first two digits is the third digit. If the first two digits are 24, their sum is 6 which is not a choice. 24 is then eliminated as possibility and we are forced to conclude that the first two digits are 12, and that makes the first three digits 123.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Considering the third condition that the second half of the fourth, the forth digit must be two times two is four. So far, 1234.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Finally, the last condition says the fifth digit is the sum of the first and fourth. 1 plus 4 is 5, hence the entire number is 12345.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John
\n" ); document.write( "
\n" ); document.write( "My calculator said it, I believe it, that settles it
\n" ); document.write( "
\"The

\n" ); document.write( "
\n" ); document.write( "
\n" );