document.write( "Question 461079: if you need 50lbs of an alloy that is 50% nickel how many pounds of an alloy with 80% must be mixed with an alloy that is 40% nickel \n" ); document.write( "
Algebra.Com's Answer #316259 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
With problems like this, you have to keep track of how much \"pure\" stuff you need.
\n" ); document.write( "It says you need 50 lb of 50% nickel.
\n" ); document.write( "50*.5 = 25 lbs of pure nickel
\n" ); document.write( ".
\n" ); document.write( "The total of 50 lb is divided between the amount of 40% nickel and 80% nickel
\n" ); document.write( "x = the amount of 40% nickel
\n" ); document.write( "(50-x) = the amount of 80% nickel
\n" ); document.write( ".
\n" ); document.write( ".4x + .8(50-x)=25
\n" ); document.write( ".4x + 40 - .8x = 25
\n" ); document.write( "-.4x = -15
\n" ); document.write( "x = 37.5 lb of 40% alloy
\n" ); document.write( ".
\n" ); document.write( "50-x = 12.5 lb of 80% alloy
\n" ); document.write( ".
\n" ); document.write( "Check your answer.
\n" ); document.write( ".4*37.5 = 15
\n" ); document.write( ".8*12.5 = 10
\n" ); document.write( "15+10 = 25
\n" ); document.write( ".
\n" ); document.write( "Done. \n" ); document.write( "
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