document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=449252>Question 449252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi, suppose you need to give a patient 40% potassium in saline, but all you have to hand is 20% in 1 litre (1000ml, how much would you give, Someone said 2 1 litre bags of the 20% saline, but you need half the volume to increase the concentration, would you give 500mls over 2bags of 20% saline? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #316247 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=316247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1(.20)+x(1.00)=.40(1+x)<BR>\n" );
document.write( ".20+x=.40+.4x<BR>\n" );
document.write( ".6x=.20<BR>\n" );
document.write( "x=.2/.6=.33<BR>\n" );
document.write( "I would add 1/3 liter of pure potassium in saline to the litre of 20% saline I already had to make 1-1/3 litres of 40% potassium saline.. </SPAN>\n" );
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