document.write( "Question 459118: how do you graph x^2+y^2+12x-6y-9=0 \n" ); document.write( "
Algebra.Com's Answer #316243 by lwsshak3(11628)\"\" \"About 
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how do you graph x^2+y^2+12x-6y-9=0
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\n" ); document.write( "x^2+y^2+12x-6y-9=0
\n" ); document.write( "completing the square
\n" ); document.write( "(x^2+12x+36)+(y^2-6y+9)=0+36+9=45\r
\n" ); document.write( "\n" ); document.write( "(x+6)^2+(y-9)^2=45
\n" ); document.write( "This equation is a circle with center at (-6,9) and radius=√45=6.7..
\n" ); document.write( "see graph below:
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\n" ); document.write( "y=(45-(x+6)^2)^.5+9
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