document.write( "Question 460772: How much of an alloy that is 10% copper should be mixed with 500 ounces of an alloy that is 70% copper in order to get an alloy that is 30% copper? \n" ); document.write( "
Algebra.Com's Answer #316225 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! 500x.7=350 \n" ); document.write( ".1x+350=.3(x+500) \n" ); document.write( ".1x+350=.3x+150 \n" ); document.write( ".2x=200 \n" ); document.write( "x=200/.2=1000 \n" ); document.write( "You need 1000 ozs. of 10% copper for the mix.. \n" ); document.write( " |