document.write( "Question 460772: How much of an alloy that is 10% copper should be mixed with 500 ounces of an alloy that is 70% copper in order to get an alloy that is 30% copper? \n" ); document.write( "
Algebra.Com's Answer #316225 by jorel1380(3719)\"\" \"About 
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500x.7=350
\n" ); document.write( ".1x+350=.3(x+500)
\n" ); document.write( ".1x+350=.3x+150
\n" ); document.write( ".2x=200
\n" ); document.write( "x=200/.2=1000
\n" ); document.write( "You need 1000 ozs. of 10% copper for the mix..
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