document.write( "Question 460962: If the endpoints of a diameter of a circle are (4,3)and (-3,5), what is the equation of the circle?
\n" ); document.write( "This is my answer is this right, if not what is?
\n" ); document.write( "Answer
\n" ); document.write( "(5-3)^2+(-3-4)^2
\n" ); document.write( "=2^2+(-7)^2
\n" ); document.write( "=4+49
\n" ); document.write( "=53
\n" ); document.write( " radius=53/2
\n" ); document.write( "midpoint : (1/2, 4)
\n" ); document.write( " equation of the circle=(x-1/2)^2+(y-4)^2=53/4
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Algebra.Com's Answer #316205 by Gogonati(855)\"\" \"About 
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Since we know the coordinates of the endpoints of the diameter we can find the coordinate of the center:\r
\n" ); document.write( "\n" ); document.write( "\"h=%28-3%2B4%29%2F2=1%2F2\" and \"k=%285%2B3%29%2F2=4\", thus the circle is centered at \r
\n" ); document.write( "\n" ); document.write( "(1/2, 4). Now we need to find out the radius of the circle:\r
\n" ); document.write( "\n" ); document.write( "\"r%5E2=%28-3-4%29%5E2%2B%285-3%29%5E2=49%2B4=53\". As we know the equation of the circle in \r
\n" ); document.write( "\n" ); document.write( "standard form is : \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\", substituting our values we get:\r
\n" ); document.write( "\n" ); document.write( "\"%28x-1%2F2%29%5E2%2B%28y-4%29%5E2=53\", which is the equation of our circle.
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